Refer to explanation
We have that
##sin(150)=sin(180-30)=sin30=1/2##
##csc(150)=1/sin(150)=2##
##cos (150) = –cos(30) =-sqrt3/2 ##
##sec(150) = 1/cos(150)=-2/sqrt3##
##tan(150)=-tan(30)=-sqrt3/3##
##cot(150)=1/tan(150)=-sqrt3##
How do you find the 6 trigonometric functions for 150 degrees?
Refer to explanation
We have that
##sin(150)=sin(180-30)=sin30=1/2##
##csc(150)=1/sin(150)=2##
##cos (150) = –cos(30) =-sqrt3/2 ##
##sec(150) = 1/cos(150)=-2/sqrt3##
##tan(150)=-tan(30)=-sqrt3/3##
##cot(150)=1/tan(150)=-sqrt3##
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