Have a look:
You can write: ##sqrt(64/100)=sqrt(64)/sqrt(100)=## and solve the two (exact) roots separately! So you get: ##8/10=4/5##
Have a look:
You can write: ##sqrt(64/100)=sqrt(64)/sqrt(100)=## and solve the two (exact) roots separately! So you get: ##8/10=4/5##