How do you solve ##Sin(pi/2 – x) cot(pi/2 + x) = -sin x## from 0 to 2pi?

undefined equation.

sin (pi/2 – x) = cos x (supplementary arc) ##cot (pi/2 + x) = (cos (pi/2 + x))/(sin (pi/2 + x)) = sin x/(-cos x).## The left side of the equation simplifies to: ##(cos x)(sin x/(-cos x)) = – sin x##, Then, the equation reduces to: -sin x = – sin x The equation is undefined. It is insolvable.