##4NO_2+O_2rarr2N_2O_5##

(a)

Since 1 mole of ##O_2## is used up for every 2 moles of ##N_2O_5## formed the rate of formation of ##N_2O_5## will be twice the rate of disappearance of ##O_2##.

(b)

Since 4 moles of ##NO_2## are used up for every mole of ##O_2## the rate of disappearance of ##NO_2## will be 4 times the rate of disappearance of ##O_2## = ##4xx0.0037=0.0148 mol.l^(-1).s^(-1)##

##4NO_2+O_2rarr2N_2O_5##

(a)

Since 1 mole of ##O_2## is used up for every 2 moles of ##N_2O_5## formed the rate of formation of ##N_2O_5## will be twice the rate of disappearance of ##O_2##.

(b)

Since 4 moles of ##NO_2## are used up for every mole of ##O_2## the rate of disappearance of ##NO_2## will be 4 times the rate of disappearance of ##O_2## = ##4xx0.0037=0.0148 mol.l^(-1).s^(-1)##