##”Ca”””_3″N”_2##
The correct answer is ##Ca_3N_2##.
Let us see how we got the answer; Look at the electronic arrangement of Ca and N atom.
Ca ( Z= 20) has 20 electrons with following electronic configuration. 1##s^2##2##s^2##2##p^6##3##s^2##3##p^6##4##s^2##.
It loses two electron in its 4s subshell to achieve stability and forms ion ##Ca^(2+)##.
##Ca^(2+)## = 1##s^2##2##s^2##2##p^6##3##s^2##3##p^6##
N ( Z=7) on the other hand has seven electrons and wants to gain three electrons to achieve stable noble gas configuration.Nitrogen atom on gaining three electrons forms negative nitride ion, ##N^(3-)## ion.
N ( Z=7) = 1##s^2##2##s^2##2##p^3##
##N^-3## = 1##s^2##2##s^2##2##p^6##
Two Nitrogen atoms gains three electrons each ( total of six) from three Ca atoms, each Ca atom loses two electrons (total of six) to two Nitrogen atom , in this process each Ca atom becomes ##Ca^(2+)## ion and nitrogen atom after gaining three electrons becomes ##N^(3-)## ion.
so in all we have three ##Ca^(2+)## ions and two nitride ##N^(3-)## ions. so the formula becomes ##Ca_3N_2##.
