Use the equation and plug in the center and the radius.

##(x+2)^2+y^2=25##

Recall the equation for a circle:

##(x-h)^2+(y-k)^2=r^2##

Where ##(h,k)## is the center of a circle with radius ##r##.

Therefore, a circle with radius ##5##, centered at ##(-2,0)## has the equation:

##color(red)((x+2)^2+y^2=25##

And the graph would look like

graph{(x+2)^2+y^2=25 [-14.24, 14.24, -7.12, 7.12]}

Use the equation and plug in the center and the radius.

##(x+2)^2+y^2=25##

Recall the equation for a circle:

##(x-h)^2+(y-k)^2=r^2##

Where ##(h,k)## is the center of a circle with radius ##r##.

Therefore, a circle with radius ##5##, centered at ##(-2,0)## has the equation:

##color(red)((x+2)^2+y^2=25##

And the graph would look like

graph{(x+2)^2+y^2=25 [-14.24, 14.24, -7.12, 7.12]}

Use the equation and plug in the center and the radius.

##(x+2)^2+y^2=25##

Recall the equation for a circle:

##(x-h)^2+(y-k)^2=r^2##

Where ##(h,k)## is the center of a circle with radius ##r##.

Therefore, a circle with radius ##5##, centered at ##(-2,0)## has the equation:

##color(red)((x+2)^2+y^2=25##

And the graph would look like

graph{(x+2)^2+y^2=25 [-14.24, 14.24, -7.12, 7.12]}